x^2-1672x+33600=0

Solution for x^2-1672x+33600=0 equation:

x^2-1672x+33600=0

a = 1; b = -1672; c = +33600;
Δ = b2-4ac
Δ = -16722-4·1·33600
Δ = 2661184
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

The end solution:

$\sqrt{\Delta}=\sqrt{2661184}=\sqrt{64*41581}=\sqrt{64}*\sqrt{41581}=8\sqrt{41581}$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-1672)-8\sqrt{41581}}{2*1}=\frac{1672-8\sqrt{41581}}{2}
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-1672)+8\sqrt{41581}}{2*1}=\frac{1672+8\sqrt{41581}}{2}
$